Quote:
Originally Posted by
MHF
Quote:
Originally Posted by
MHF
--->
The Story of Doctor Dolittle, Being the History of His Peculiar Life at Home and Astonishing Adventures in Foreign Parts. [
1st spot.]
You Are Awesome: Find Your Confidence and Dare to be Brilliant at (Almost) Anything. [Last, at the
606th spot = {6 * [antilog(6^0)]^2 + 6} --->
666]
https://anagram-solver.net/besttofin...s?partial=true
Again, I wonder how long the first, and last, thus solutions will hold. But, if not, then can it be thus patched up again, by adding yet another set of 0 / 1 for an o, with an l, or i?
Taking out another o would remove the first thus solution above, and, so, taking out another 0 / 1 with an o, with an l, or i, respectively, can't work, even if the last thus solution were retained. So, even though I knew that something, eventually, was to change by the addition of new thus solutions, between the first, and the last, I didn't know exactly what. Now I see.
Interestingly, with an additional two thus solutions, the last thus solution above went to spot #
607, if put the first thus solution back to spot #
0, for 607 = (1 + 606) = [1 + (6*100 + 6)] ---> 1/
616 . Good thing that I went with the
666 above, for the final of finals follow-up post to be another reciprocal in also this way.
Quote:
What others think of me isn't important, because I make the universe my audience, not, people, in that it's the laws of the universe that demand respect. Nothing more worthless than the laws of men, made, and altered, to suit men. No man, truly, has anything of value to offer to me. Like believing that Christ died for no one but Himself, that He merely showed us the way to do as He.
https://youtu.be/b0B3VEsHz7U
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229 -------------> 229 = [1 + (220 + 2^3)] ---> 1/
222