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A woman named Sherry had our child. She was in her early 20's, she already had one child with her ex-husband (she has full custody and he's not even in the picture) and was pregnant with her second....

My family is exactly as real as your family.

The only sensible course is to have a separate (but equal) institution for us? Really?

It makes as much sense for gays to get married as it does straights. Realize that we gays can also have...

I am a gay man. And not surprisingly, I disagree with some of your assertions about me and people like me.

At no point did I choose to be different. I just was different. What I did choose was...

This information is not on the original problem. We do not know the peeker/caller's "strategy." If we knew the "strategy" then we could analyze that.

For example, if the peeker picks a die at...

True, English is English. Unfortunately, English is full of ambiguities. For example:



Your interpretation of this statement is different from OneHitWonder's interpretation. You understand...

I do not agree with your assertion that "one or the other die is a 2" is different from "at least one of the dice is a 2." To me, the statement "at least one of the dice is a 2" means either the...

If we want to consider only the outcome of that ONE THROW with the outcome known by the peeker (as he has seen both dice), then here's the probability: If the peeker saw 2-2, then the probability is...

Alright, I'll do it your way. I'll take "the one showing a 2" and fix it as the first die. So there are 6 outcomes: 2-1, 2-2, 2-3, 2-4, 2-5, 2-6.

There are 2 ways to roll each of 2-1, 2-3, 2-4,...

Please explain to me the error in my analysis. All I've ever heard from you is some form of "No, that's wrong" with no actual explanation of why it is wrong.

It is correct that when the first die landed on 2, there is a 1/6 chance that the second die also landed on 2 (6 possible outcomes, 1 success).
It is correct that when the second die landed on 2,...

Please explain to me how a die that immediately settles on 6 plus a spinner that eventually settles on 2 does not conform to the condition "at least one of the dice is a 2."

If the first die is not a 2, then there is still the possibility of the original question applying. That is my point.

How does the case where the die that immediately comes to rest on a number other than 2 and the spinner eventually settles on 2 not satisfy the condition that at least one of the dice is a 2?

I did not change the conditions on your example. I showed a condition that your example does not consider, but is covered by the conditions of the original question.

This is not the same question because it does not include every situation that the original question does. The original question considers rolls where at least one die is a 2. The spinner example...

Alan, at this point I am trying to understand how you read the question. I understand fully well, that based on your understanding of the question, the answer is 1/6. Based on my understanding of...

Can you tell me out of the 36 ways to roll 2 dice, how many of those ways satisfy the condition "Die #1 is a 2 and die #2 is any of the six numbers on that die. Or you can reverse this so that Die...

Or would you say how many combinations of the dice satisfy the condition "at least one of the dice is a 2", and how many combinations of the dice satisfy the condition "both of the dice are a 2"?
...

Because his bet has 1 way to win, 10 ways to lose, and 25 ways to push.

2-2 on the hop has 1 way to win and 35 ways to lose.

I agree. I'm sorry I couldn't be of any help.

2-1 and 1-2 both satisfy the condition that one of the dice is a 2. Why then are you only considering 2-1 and not 1-2?

Are you able to understand the difference between 2-1 and 1-2?

So, by your logic, rolling 2-2 and 1-2 have the same probability?

Then what is the probability of rolling ace-deuce, if at least one of the dice is a 2?