Search:

Huh? What?

Failure in comprehension. What we do is give you a reminder there are two dice to consider and not one. You can't come after the throw and eliminate anything. That's the outcome now. You don't mess...

Why would you (and Alan) expect a die to change it's value? Don't get ridiculous now.
Instead, you need to only comprehend that you are dealing with two dice and either one of them can become a two....

I did address it, I believe.
You roll one die - the odds of it to stop on 2 is 1/6. When it stops at 2 it is a 2 for eternity.

Now, add another die. Same thing - the odds of it to stop on 2 is...

You don't have to. The only thing you need to comprehend is the experiment begins with the throw of pair of dice. All consecutive probabilities stem from there.

Not with setting one die and now...

You are not allowed to remove one die. You only know "at least one of the dice" is 2. That makes it possible for any die to be 2. If you go ahead and remove one die , you don't see the problem in...

I believe you are quite wrong here.
The real problem for you is you think the people able to perceive 1/11 are deluded theorists and not "grounded" like yourself.
What the situation actually is,...

Any thoughts on this?
What does the real, physical world say about the odds?
What does it say when we experiment one time across many experimenters?

How come all of them agree it is 1/11?
Where...

Also, why are all 1/6-ers forgetting/not commenting (excluding Alan's ridiculous views) the fact that the bet from page 1, based word by word on the question is yielding 1/11?
Is it because they...

Try to rationalize on the example with the 36 cards. It demonstrates in a very simple terms why the odds of 2-2 are to be considered only in conjunction with what the odds of 2-x were prior to the...

I'm using "nonsense" as a short and to the point way to express my believe you are barking the wrong tree here with your desire to dismantle a simple logical math question into philosophical argument...

Not quite sure about that.
It seems it is new information for you that whether you do a one time experiment or multiple times doesn't matter and the odds are still the same.

It is quite new info...

But it doesn't matter how is this question interpreted regarding one time action or multiple experiments. The odds hold true every single time and it is not 1/6, so why are people blaming the...

Well, that's one of the conditions as clarified like million times after the initial few posts on the old discussion. Have you missed it?



What's this nonsense?



Wow, you're loosing it....

Because they are related to everything, why can't you get it?



What's worse parrot or bigot not capable to comprehend neither math nor words?

Here is your one time throw example:

I, Bob,...

It does not matter if we are talking single, one time throw or not. The odds are still the same.

No, I'm not misapplying anything. The bet you agreed represents the question straight as it was written and clarified, proves me right.

And indeed there is nothing much to say here. The odds are...

Two dice make eleven combos representing 2-x, are they not?
So the odds for us to see 2-x are 11/36 are they not?
Now this above IS NOT IRRELEVANT to the odds of us seeing 2-2.
You 1/6ers are all...

LOL.
Okay try and read some books, maybe it will help.

Now, you admit the answer to the question without peeker, cup etc is 1/11. Good. We have improvement.

What in the writings of the OQ makes you think it is different than this new question? What?
...

Here is another question on conditional probability involving dice:

http://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.434512.html
...

Nope its your error. Please try to think it through.
Or are you saying that when you roll a pair of dice or toss a coin or spin a roulette wheel the odds are different depending on whether you do it...

It is not a new question, I posted it at least 5 or 6 times till now, and only now you decide to address it.

And the first question is not mine(neither is the second one but nevermind) or maybe...

The way to get to 2-2 is dependable to the ways to get to 2-x. They are not undependable events.

See here how and why computing probability of dependable events needs to account of all ways to...

Mmmm... what does the peeker do other than informing us we are now witnessing one of 11/36 possible event?
How is it different from judging the odds for an event which happens 1 time of every 11...