Originally Posted by
OnceDear
ok. Thanks Alan, I will continue tomorrow, as time permits.
14. Can you see that Probability of Deuce result from a single die, could be expressed as "We expect that if we throw the single die a lot of times, it will land as a deuce approximately 1 in 6 times"
Do you agree with and fully understand that? YES
15. Now we need to explore this a tiny bit and get back to the concept of 'A Qualified Event'
E.g. 'If the roll of a single die is an even number, then what is the probability of it being a two?
To calculate that, we would use . . .
Probability = P(DeuceWhenEven) = (count of the number of qualifying ways that it might land as a deuce and be an even number)/(count of all the qualifying ways it might land as an even number)
We could work that out correctly as the 'probability of it being a deuce ( When we know it's even)' = Probability = 1/3
Are we still fully in agreement? HERE'S WHERE I HAVE TO SAY I CAN'T RESPOND. I WOULD HAVE TO LOOK AT THIS MORE CLOSELY SINCE IT'S NOT SOMETHING I AM FAMILIAR WITH, AND MY TV SHOW JUST COMPLETED AND I HAVE TO LOOK AT EMAILS AND WEB TRAFFIC DATA, BUT PLEASE PROCEED BECAUSE I AM FOLLOWING YOU.
We would NOT work it out and come up with P(DeuceWhenEven) = 1/6, because to do so would be to ignore the qualifier in the question.
Do you agree with that? I DON'T KNOW WHAT THE RELEVANCE OF THIS IS, BUT PLEASE PROCEED.
Do you agree so far? We covered some ground there.