Originally Posted by
Rob.Singer
Alan, I told you in my last post that the 6-1 position has always been only if they removed the die showing the 2 from the scene. One die remaining = six opportunities to yield a 2. That should be clear, and this is always been how I've interpreted the OQ.
The "WoV camp" has always used the interpretation that it is always a two-dice event without removing the die showing a 2 from play. I've said many times I didn't believe the OP meant the problem to be like this, but I guess you've agreed that it should for betting purposes.
Look at the combinations arci just posted--those are the 11 possibilities when both dice remain in play. In this case, naturally 9-1 is bad odds. In your discussions with the WoV folks, when & where did you stop talking about one of the dice being removed from play? I've said I'd take the bet at 9-1 only if the original die showing a 2 were removed from play, "until the cows come home". But I just looked at wizard's site, and of course the poster named "RS" cut & pasted snippets of my post here that is incomplete, not all correct, and said in a way that shows he's irritated. He also left out their Achilles heel about betting that I'll win with my strategy. I said I'd take the bad bets for $10 IF there was the bet on my strategy this weekend in Tahoe. I'd love to do that because at $10/roll my losses wouldn't be much, but I'd likely win $2500 from them on my vp play.
Do you understand this now? Remove one die = 6-1; keep both dice = 11-1. That has always been why the question was "tricky". Two interpretations.