Let n=the number of games of Baccarat played by the casino patron for the "session" (whatever the fuck that even means - like Max wrote)
Let X be the following step function:
X=(n/2)+1 if N is even
X=(n/2)+0.5 if N is odd
Also ( using Don's win probability)
p=.45
q=1-p
The probability of being ahead by one game during the Session is (this calculation needs to also be done for the probability of being ahead by 2 games and so on up to n and then these N-x+1 probabilities need to be summed to get the total probability):
Now we just need to do this for every game on the floor (if you're well connected like Advantage Play you can get the par sheets for all the slot games) including live poker and sports book bets which should be fun. Following by weighting each probability by its n before summing them all up and dividing that total by the sum of all the Ns to get the final probability (weighted average).
What is that final weighted average ? And is it equal to or greater than 0.7 ?