Originally Posted by

**MHF**
**17308926** = (1^**7** + 7^**2** + 3^**0** + 0^**9** + 8^**8** + 9^**6** + 2^**1** + 6^**3**), with exponents, 7, 2, 0, 9, 8, 6, 1, and 3.

So how about turning around the above, in an effort to finish off the thus stuff?

7^

**1** + 2^

**7** + 0^

**3** + 9^

**0** + 8^

**8** + 6^

**9** + 1^

**2** + 3^

**6** =

**26855778**, which doesn't share the same outright property as

**17308926**, in terms of using each of the digits, 0, 1, 2, 3, 6, 7, 8, and 9.

However, something works, say,

**26855778** = (26891730 - 35952) = [

**26891730** - (35953 - 1)], with the red digits above almost as before, but, in a backward sense, and, (35953 - 1) ---> 1/

**359**_

**953** .

So how about another song, this one at a time of

**3**:

**59**?

Oh, almost forgot to do the (100000000 -

**26855778**) = 73144222, thing, but, with the entire numeral, which then goes to 1/

**731**_

**142** .

Interestingly, if go the route of PYB's original thus notion, then (2^6+8^5+5^7+7^8) = 5875758 ---> (10000000 - 5875758) = 4124242 --->

**142**, I think, by bringing the 1 to the front.