Originally Posted by
MHF
17308926 = (1^7 + 7^2 + 3^0 + 0^9 + 8^8 + 9^6 + 2^1 + 6^3), with exponents, 7, 2, 0, 9, 8, 6, 1, and 3.
So how about turning around the above, in an effort to finish off the thus stuff?
7^
1 + 2^
7 + 0^
3 + 9^
0 + 8^
8 + 6^
9 + 1^
2 + 3^
6 =
26855778, which doesn't share the same outright property as
17308926, in terms of using each of the digits, 0, 1, 2, 3, 6, 7, 8, and 9.
However, something works, say,
26855778 = (26891730 - 35952) = [
26891730 - (35953 - 1)], with the red digits above almost as before, but, in a backward sense, and, (35953 - 1) ---> 1/
359_
953 .
So how about another song, this one at a time of
3:
59?
Oh, almost forgot to do the (100000000 -
26855778) = 73144222, thing, but, with the entire numeral, which then goes to 1/
731_
142 .
Interestingly, if go the route of PYB's original thus notion, then (2^6+8^5+5^7+7^8) = 5875758 ---> (10000000 - 5875758) = 4124242 --->
142, I think, by bringing the 1 to the front.