Originally Posted by tableplay View Post
Originally Posted by accountinquestion View Post
Lets talk about the math and stop trolling.
This is a very straightforward problem. That is, the probabilities are the same as those encountered in compositional strategy. For example, given your three cards (two initial cards plus the double down card) and the dealer's upcard (and I suppose the other players' cards if that information is available), you would decide whether to take a 2nd double down card (on a glitched machine) using the exact same criteria you would use under the scenario where you have not doubled down.

Working Example on a hypothetical glitched machine:
1. You are dealt a 6 and 5 with the dealer's upcard being a 10 and you decide to double down since it is +EV to do so (Hi-Lo neutral count).
2. You get a 2
3. So (with double the money in action) now you have a 6,5, and 2 versus the dealer 10 and you would hit. The explanation for this is already described above but is clarified in points 4. and 5. below.
4. If you walked up to a BJ table, started playing, and then received a 2 and 5 initially versus a 10, then you would take a hit according to basic strategy and not double down (again neutral hi-lo count). Receiving a 6 on your third card, you would then take another card since you would hit on a 13 (2,5,6) versus a dealer 10.
5. The order of reception is different than the double down scenario but the action is the same, you take another card when you have a 6,5, and 2 in your hand versus a dealer 10. You are making things worse on yourself (i.e. losing even more in this already -EV spot) if you do not do this.
Yea good post. Granted I didn't think about it to actually try and figure it out but it is just the same basic strategy. Kewl could have snooped around and gotten a perfect answer. Weird. Actually I think it would be obvious to any BJ player who was sitting in that situation.