Originally Posted by
MHF
Originally Posted by
MHF
Interestingly, if go the route of PYB's original thus notion, then 26855778 ---> (2^6 + 8^5 + 5^7 + 7^8) = 5875758 ---> 5875758 = (10000000 - 4124242) ---> 1/142, I think, by bringing the 1's to the front.
Someone should similarly finish up with its corresponding term,
17308926 ---> (1^7 + 3^0 + 8^9 + 2^6) =
134217794, as another exercise in mathematical dexterity.
134217794 = [(20 + 1 + 14200)*(1000 - 142)*11 - 4] ---> 1/
142_1/
142_1/
142, which forms the last 1/
142 by wrapping the end of the expression back to its start . Interestingly, there're three of the 1/
142's in succession, like the thus result above for
5875758 .
Another way is to write the
5875758 as {100000*[(7 + 40) + 11] + 75700 + [11 + (40 + 7)*1]}, which gets back to the grafting integer
5711, and, the suicide text number,
741_
741, just like,
134217794 = {(101+757)*11*[4^0+7100+10+10+(100+7000)]-4}, except which has 1's over the
174's .
MHF MHF is online now
Gold
MHF's Avatar
Join Date
Mar 2024
Posts
137
Oh, (04:38 + 03:18) = 7:56 ---> (757 - 1) --->1/
757 .