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  1. #11
    Originally Posted by MHF View Post
    Originally Posted by MHF View Post
    Originally Posted by MHF View Post
    Interestingly, if go the route of PYB's original thus notion, then 26855778 ---> (2^6 + 8^5 + 5^7 + 7^8) = 5875758 ---> 5875758 = (10000000 - 4124242) ---> 1/142, I think, by bringing the 1's to the front.
    Someone should similarly finish up with its corresponding term, 17308926 ---> (1^7 + 3^0 + 8^9 + 2^6) = 134217794, as another exercise in mathematical dexterity.
    134217794 = [(20 + 1 + 14200)*(1000 - 142)*11 - 4] ---> 1/142_1/142_1/142, which forms the last 1/142 by wrapping the end of the expression back to its start . Interestingly, there're three of the 1/142's in succession, like the thus result above for 5875758 .

    Another way is to write the 5875758 as {100000*[(7 + 40) + 11] + 75700 + [11 + (40 + 7)*1]}, which gets back to the grafting integer 5711, and, the suicide text number, 741_741, just like,
    134217794 = {(101+757)*11*[4^0+7100+10+10+(100+7000)]-4}, except which has 1's over the 174's .


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    Oh, (04:38 + 03:18) = 7:56 ---> (757 - 1) --->1/757 .
    By way of a follow-up post, at post #138 = (1 + 137) ---> 1/137, consider that 1509 = (1609 - 100) ---> 1961, or 1691, 1510 = [1000 + (700 - 200) + 10] ---> 1721, or 1271, and, (04:38 - 03:18) = 1:20 ---> 120 = (1 + 2)*4*10 ---> 1/142.

    Anyway, see you, in the next life, or at the finals, if you make it. Remember that they're all "rabbit holes", until it's not. Over and out, G!

    Last edited by MHF; 10-02-2024 at 08:57 AM.

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