Originally Posted by Alan Mendelson View Post
It's not two throws of the dice. It's ONE THROW.
If we want to consider only the outcome of that ONE THROW with the outcome known by the peeker (as he has seen both dice), then here's the probability: If the peeker saw 2-2, then the probability is 1 in 1 that the throw was 2-2. If the peeker saw anything else, then the probability is 0 in 1 that the throw was 2-2.