Originally Posted by
champ724
if the dice were thrown one at a time the odds would be 1/11 against 2 2 idk if the peeking is the same as them being thrown one at a time but once the first dice is on 2 then its a 1/6. so once both dice are sitting there and one is on 2 the chance of the other die being on 2 is 1/6.