Originally Posted by
a2a3dseddie
How about this:
In a standard game of craps considering only the rolls where "At least one of the dice is a 2." What are the odds of being paid on a Hard 4 bet?
Let's see, you CAN'T have an "easy 4" since you know "At least one of the dice is a 2." so 1,3 or 3,1 have been ruled out.
So, your only loss comes if a 7 appears... 2,5 or 5,2
The odds of a 5 appearing on a single die is 1/6 (the same as another 2 appearing).
Do you think it's an even money bet by disregarding the possibility of a 5,2? And what wording in the original question would make you disregard the possibility of 5,2?
Or are the odds actually 2-1 against you? (2,5 or 5,2 versus 2,2)