Originally Posted by a2a3dseddie View Post
Originally Posted by Alan Mendelson View Post
You are told TRUTHFULLY that at least one of the two dice in the cup is showing a 2. So again, what are the odds that the second die is also showing a 2? It is still 1/11 for a six sided die? Or is it 1/6?

Respond to the question and its conditions.

The condition is one die is known to be a two. It is not the same as throwing two dice simultaneously and knowing that there are 11 combinations showing at least one two. Repeat: it is not the same as throwing two dice simultaneously and knowing that there are 11 combinations showing at least one two.

This is a reading comprehension issue for those of you who think the answer is 1/11.
Once again here is the original problem:

You have two 6-sided dice in a cup. You shake the dice, and slam the cup down onto the table, hiding the result. Your partner peeks under the cup, and tells you, truthfully, "At least one of the dice is a 2."
What is the probability that both dice are showing a 2?

That is the original question.

NOT

"what are the odds that the second die is also showing a 2?"
Amazing to check in to see this still rages on. Eddie's post here and the one in which he stated "arci, in Alan's defense" really defines everything this dice issue is about.

There are absolutely two answers to this "problem" and either is correct depending on how the reader wants to understand the question. Redietz actually identified the complexities of how different individuals might understand the problem, albeit a bit awkwardly as usual.

The "math people" like arci as well as several of these uneducated self-proclaimed "AP's who've been imported from the WoV site, along with the mensa "geniuses" that come out of the infamous pool of libtard atheists, agnostics, queers, and weirdo transgenders over there, all see this problem as a one-way street leading to an 11 to 1 conclusion. In arci's defense, he's a hard core technical person, and he is infinitely trained to see this problem--and its final solution--in only one way: to be an 11:1 result and that is all there is to it. The rest of the 11:1 crew? RS__ & jbjb are simply responding the way they best believe they won't be chided or mocked over on WoV. In other words, they really cannot think for themselves. Mickey however is doing nothing more than taking the opposite position of whatever Alan comes up with because he's always been jealous of Alan and his money, his string of girlfriends, his job, and his basic everyday normal life compared to that of the lowlife, non-productive slug existence mickey endures.

On the other, more grounded side of this resides the people who have no interest in reading anything more or less into the problem than it simply states....while 100% ignoring anything that it may imply. These people seek out an everyday-type answer laced with common sense...and nothing more. And while their adversaries' chief goal is very likely to be making others think how deeply intelligent they can be while the rest of the "dummies" can never attain their special level of being able to dissect and analyze such a problem in ways only a class of Einsteins may begin to understand them, the dumbos know how to "keep it simple, stupid".

So who's got it right? Well, both sides have made an indisputable case for their argument (belief). But it is not really that difficult a problem to figure out--one need not have an engineering degree or be a math or psychology professor at Stanford or Boston College (I had to throw that in ) to come up with a conclusion. It all depends on your reading comprehension.

HOWEVER, if I were a court appointed arbitrator I would rule solidly in favor of the "6" crowd, while giving the "11" crowd honorable mention for their deep insight, unforeseen complex problem solving abilities, ingenuity, and overall argumentative tenacity. Why? Because NOWHERE IN THE ORIGINAL STATED PROBLEM DOES IT MENTION ANYTHING OTHER THAN A ONE TIME TRIAL. If the peeker sees only one die and it is a 2, or if he sees both dice and at least one of them is a 2--and because he doesn't identify which is the case--"6" wins as the simple, common sense conclusion.

Good luck.