All that tells us is that the peeker has determined 1 of the 11 possible combinations containing at least one 2 is under the cup. That's all he tells us.Originally Posted by Alan Mendelson
Any of 36 combinations can be under the cup until someone looks.Originally Posted by a2a3dseddie
In this case, someone looked and found at least one of the two dice is showing a 2.
That leaves 6 possible faces on the second die.
How many times do we have to go over this?
Of those 11 possible combinations that could be under the cup, only one combination is 2 2.
Ten combinations are not.
The question asks for the probability that both dice are showing a 2.
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