Originally Posted by quahaug View Post
You'll just have to accept it as the fact that it is. Maybe after all is said and done you just need to take it on faith. My personal belief is you're just trolling/flaming the thread. It's hard to believe someone could be as stubborn as you make yourself out to be. It's hilarious to me though so cognitive dissonance yourself away..
Originally Posted by a2a3dseddie View Post
Using red and green dice what is the probability you'll start with the red dice (or green) as the 2? Remember, we are NOT factoring in any of the non-2 containing dice combinations.

1. There are 11 combinations, and 6 of those 11 could start out with the red die as the 2. This is the first probability you have to overcome.

2. Once the red die is a 2, of course there is a 1/6 chance the green die could be a 2.

3. These 2 probabilities are multiplied together to get 6/11 X 1/6 = 6/66 or 1/11.

You seem to be stuck on step 2, completely disregarding step 1.

Now let's talk about two red dice that are shaken in a cup and slammed down on a table. One person peeks and sees that at least one of the two red dice is showing a 2.

Both of you are unable to show me 11 possible options. You say they are there and you ask me to trust that they are there but you can't demonstrate that they are there.

You can't demonstrate the 11 possible options because 11 possible options in the real world do not exist -- not with two dice with at least one of those two dice already showing a 2.

In order to show 11 options you have to rotate the dice showing a 2 to show other faces. Or you take Arc's out of the world approach and you claim that there is no proof that any die shows a 2 even though the original problem tells us that at least one die shows a 2.

Never has anyone from the 1/11 camp shown that there are 11 faces or combinations to consider. Never. Never.

And frankly you can't because that's the way it is in the real, physical world when you have two real physical dice.

You can show me all the graphs and charts you want with all of the combinations of two dice, and you can point to all of those combinations but when it comes to using two real dice, with at least one die showing a 2 all of your theory does not apply. Because the theory does not apply AFTER the roll of the two dice and AFTER one of the two dice is known to be a 2.

Your theory only looks at possible combinations and it looks at the possible combinations using all of the faces of two dice. Remove one die because the face is known on that die, and your theory is no longer applicable to the question.

Once again, I invite you to take two physical dice, roll them, and when at least one die is showing a 2, prove to me there are 11 faces to be considered. Do it. Do it. Do it.

You can't. You just can't.