Originally Posted by Alan Mendelson View Post
When rolling two dice simultaneously, 2-2 shows up 1/36 times.
There are 11 combinations showing at least one 2, and only one combination that shows 2-2. So you are facing 10 losing decisions for each winning decision.
So what reduces the 1/11 scenario you describe here to 1/6 after you put both dice both in a cup, roll them simultaneously, and a peeker says at least one of the dice is a 2?